![]() ![]() |
May 12 2008, 10:54 PM
Post
#1
|
|
|
SuperNova III Member Group: Support Team Posts: 2,141 Joined: 2-November 02 From: Toronto Member No.: 302 ![]() |
It was 2.5 years ago when I was shopping for a laptop & I asked the very same question here but despite my hard research & other people's help, I could not get a precise answer to this.
Yesterday, just by accident I came across this 5 pages of noteworthy article which solved this mystery for me & put an end to my never-ending nightmares! On page 5, you will find this: QUOTE Each instruction code, memory address, etc. will take up more room in your RAM and cache due to the increased length of pointers, protected space, etc. Where a 32-bit OS may be able to execute a program in 100MB, you can find that the size of a 64-bit OS running the same program can take 105-110MB. Often times this isn't the case, but it is an important consideration. Caution: the article starts with the basics that could be offending to technical audience! Viewers desecration is advised!) |
|
|
|
![]() ![]() |
|
Lo-Fi Version | Time is now: 24th May 2013 - 03:04 AM |